Look at the section on Number to Algebra for ideas on how to introduce Algebra Tiles.
This activity introduces expressions with unknown variables and constant terms.
Also available expressions with variable -10<x <10
Ask students to match the models to the statements. Ideally they should already be familiar with base blocks and algebra tiles.
Next move the change x slider above to show that x is variable and the units are constant.
The expressions can be manipulated using Mathsbot to highlight the distributive property 2(x+3) = 2x + 6.
Using the rectangle representation links to the area model for multiplication and division and highlights the common factor of 2.
Move the slider to change the value of x. When does 3x + 2 = x + 6?
When is 3x+2 > x+6?
When is 3x+2 < x+6?
Making connections between the bar model and the graph model.
Change the number bars, size of constant term and position using the sliders.
Compare 3x and x+3
Change the value of x by moving the sliders
Solve equations and inequalities by moving the slider and comparing the bar model to the graph.
Algebra tiles do not show equality and inequality.
Before using algebra tiles to solve equations represent equality and inequality using a bar model or a dynamic model like equal expressions above.
Add multiples of x’s, -x’s, 1’s or -1’s to both expressions to isolate x on one side of the equation.
This method will always work and leads to the standard balancing method.
3 - x + x = x - 4 + x
3 + 4 = 2x - 4 + 4
Change x and y until the bars are equal.
The elimination method is clear to see using algebra tiles and zero pairs when the coefficients have opposite signs.
2x + y = 7
x - y = 2
Add the two equations together to get the image below.
3x + y - y = 9
The zero pair highlights the elimination.
3x = 9
x = 3
Substitute into 2x + y = 7
6 + y = 7
y = 1
x = 3 and y = 1
From here you can move on to multiplying one and then both equations before eliminating by adding the equations.
Difficulties and misconceptions start when the coefficients are the same sign.
Method 2 also avoids the difficulties that arise in questions that involve subtracting negatives.